Update composition-api.md#3430
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inject() uses a key, but the argument of that was 'foo', which is the value not the key.
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inject() uses a key, but the argument of that was 'foo', which is the value not the key.
Description of Problem
inject uses a key, not the value. The key provided in the example is 'key'
Proposed Solution
Update the value of injection to use the 'key'
Additional Information