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1 change: 1 addition & 0 deletions databases/catdat/data/categories/Set.yaml
Original file line number Diff line number Diff line change
Expand Up @@ -17,6 +17,7 @@ related_categories:
- Set_f
- SetxSet
- Setne
- Set_arrow

satisfied_properties:
- property: locally small
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71 changes: 71 additions & 0 deletions databases/catdat/data/categories/Set_arrow.yaml
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@@ -0,0 +1,71 @@
id: Set_arrow
name: category of set functions and commutative squares
notation: $\Set^{\rightarrow}$
objects: >-
triples $(X, Y, f)$ where $X$ and $Y$ are sets, and $f : X \to Y$ is a function
morphisms: >-
a morphism $(X, Y, f) \to (X', Y', f')$ is a pair of functions $\ell : X \to X'$ and $r : Y \to Y'$ making a commutative square
$$\begin{CD}
X @>{f}>> Y \\
@V{\ell}VV @VV{r}V \\
X' @>>{f'}> Y'
\end{CD}$$
description: This category is an example of the <a href="https://ncatlab.org/nlab/show/arrow+category" target="_blank">arrow category</a> $\Arr(\C)$, where $\C$ is the category of sets. It is also known as the Sierpinski topos, since it is equivalent to the category of sheaves on the Sierpinski space.
nlab_link: https://ncatlab.org/nlab/show/Sierpinski+topos

tags:
- set theory

related_categories:
- Set
- SetxSet
- Sh(X)

satisfied_properties:
- property: locally small
proof: This is easy.

- property: semi-strongly connected
proof: >-
Consider two objects $(X, Y, f)$ and $(X', Y', f')$. If $X'$ is non-empty with element $x'$, we can construct a morphism $(\ell, r) : (X, Y, f) \to (X', Y', f')$ where $\ell$ is the constant function with value $x'$, and $r$ is the constant function with value $f'(x')$; and similarly if $X$ is non-empty we can construct a morphism $(X', Y', f') \to (X, Y, f)$. Otherwise, if $X$ and $X'$ are both empty, we can reduce to the fact that $\Set$ is semi-strongly connected to find $r$ in one direction, and fill in $\ell$ as the unique function $\varnothing \to \varnothing$.
Comment thread
ScriptRaccoon marked this conversation as resolved.

- property: Grothendieck topos
proof: It is equivalent to the category of presheaves on <a href="/category/walking_morphism">the walking morphism</a>.

- property: locally strongly finitely presentable
proof: It is equivalent to the category of models of the algebraic theory with two sorts, and a single unary operation from one sort to the other.

unsatisfied_properties:
- property: skeletal
proof: 'Consider $\id_X : X \to X$ and $\id_Y : Y \to Y$ for isomorphic but non-equal sets $X$ and $Y$.'

- property: generator
proof: >-
Suppose $\Set^{\rightarrow}$ had a generator. Then by <a href="/content/topos-with-generator">this result</a>, every subterminal object would be either initial or terminal. However, in fact, $0 \to 1$ is a subterminal object which is isomorphic to neither the initial object $0 \to 0$ nor the terminal object $1 \to 1$.

special_objects:
initial object:
description: the unique function $0 \to 0$
terminal object:
description: the unique function $1 \to 1$
coproducts:
description: component-wise defined disjoint union, equipped with the disjoint union of the functions
products:
description: component-wise defined cartesian product, equipped with the product function

special_morphisms:
isomorphisms:
description: pairs $(\ell, r)$ where $\ell$ and $r$ are both bijections
proof: This is easy.
monomorphisms:
description: pairs $(\ell, r)$ where $\ell$ and $r$ are both injective
proof: For the non-trivial direction, use the fact that the domain functor taking an object $(X, Y, f)$ to $X$ and a morphism $(\ell, r)$ to $\ell$ is representable by $1 \to 1$; and moreover, the codomain functor taking an object $(X, Y, f)$ to $Y$ and a morphism $(\ell, r)$ to $r$ is representable by $0 \to 1$.
epimorphisms:
description: pairs $(\ell, r)$ where $\ell$ and $r$ are both surjective
proof: For the non-trivial direction, use the fact that the category is epi-regular, so any epimorphism is a coequalizer; and the fact that coequalizers can be calculated component-wise.
Comment thread
ScriptRaccoon marked this conversation as resolved.
regular monomorphisms:
description: same as monomorphisms
proof: This is because the category is mono-regular.
regular epimorphisms:
description: same as epimorphisms
proof: This is because the category is epi-regular.
1 change: 1 addition & 0 deletions databases/catdat/data/categories/SetxSet.yaml
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Expand Up @@ -11,6 +11,7 @@ tags:

related_categories:
- Set
- Set_arrow
- Sh(X)

satisfied_properties:
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1 change: 1 addition & 0 deletions databases/catdat/data/categories/Sh(X).yaml
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Expand Up @@ -13,6 +13,7 @@ tags:
related_categories:
- Set
- SetxSet
- Set_arrow
- Sh(X,Ab)

comments:
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1 change: 1 addition & 0 deletions databases/catdat/data/macros.yaml
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Expand Up @@ -121,3 +121,4 @@
\Isom: \mathbf{Isom}
\Pair: \mathbf{Pair}
\Span: \mathbf{Span}
\Arr: \mathbf{Arr}