`asyncio.print_call_graph()` loses the call stack at `aiter(callable, stop_value)`

[deadlovelll]

Bug report

Bug description:

The two-argument form of aiter() hides everything the callable is waiting on. The awaitable it produces exposes nothing about the coroutine it wraps, so the walk stops there

Repro:

import asyncio

async def deep():
    await asyncio.Event().wait()

async def produce():
    await deep()
    return 1

async def worker():
    async for _ in aiter(produce, None):
        pass

async def main():
    t = asyncio.create_task(worker(), name='worker')
    await asyncio.sleep(0.05)
    asyncio.print_call_graph(t)
    t.cancel()

asyncio.run(main())

Expected:

* Task(name='worker', id=0x105e7cb90)
  + Call stack:
  |   File '/Users/timofeiivankov/cpython/Lib/asyncio/locks.py', line 210, in async Event.wait()
  |   File '/Users/timofeiivankov/cpython/repro.py', line 4, in async deep()
  |   File '/Users/timofeiivankov/cpython/repro.py', line 7, in async produce()
  |   File '/Users/timofeiivankov/cpython/repro.py', line 11, in async worker()

Actual:

* Task(name='worker', id=0x105adcb90)
  + Call stack:
  |   File '/Users/timofeiivankov/cpython/repro.py', line 11, in async worker()

CPython versions tested on:

CPython main branch

Operating systems tested on:

macOS

[deadlovelll]

@kumaraditya303