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main.cpp
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113 lines (100 loc) · 2.7 KB
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// Source: https://leetcode.com/problems/remove-duplicates-from-sorted-list-ii
// Title: Remove Duplicates from Sorted List II
// Difficulty: Medium
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Given the `head` of a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Return the linked list **sorted** as well.
//
// **Example 1:**
// https://assets.leetcode.com/uploads/2021/01/04/linkedlist1.jpg
//
// ```
// Input: head = [1,2,3,3,4,4,5]
// Output: [1,2,5]
// ```
//
// **Example 2:**
// https://assets.leetcode.com/uploads/2021/01/04/linkedlist2.jpg
//
// ```
// Input: head = [1,1,1,2,3]
// Output: [2,3]
// ```
//
// **Constraints:**
//
// - The number of nodes in the list is in the range `[0, 300]`.
// - `-100 <= Node.val <= 100`
// - The list is guaranteed to be **sorted** in ascending order.
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#include <unordered_map>
using namespace std;
struct ListNode {
int val;
ListNode* next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode* next) : val(x), next(next) {}
};
// Use counter
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
auto preHead = new ListNode(-1000, head);
auto counter = unordered_map<int, int>();
auto curr = head;
while (curr) {
counter[curr->val]++;
curr = curr->next;
}
curr = preHead;
while (curr->next) {
auto next = curr->next;
auto val = next->val;
if (counter[val] > 1) {
while (next && next->val == val) {
curr->next = next->next;
delete next;
next = curr->next;
}
} else {
curr = curr->next;
}
}
auto ans = preHead->next;
delete preHead;
return ans;
}
};
class Solution2 {
public:
ListNode* deleteDuplicates(ListNode* head) {
auto preHead = new ListNode(-1000, head);
auto curr = preHead;
while (curr->next) {
auto next = curr->next;
auto val = next->val;
// Count duplicate
auto count = 0;
while (next && next->val == val) {
count++;
next = next->next;
}
// Delete
if (count > 1) {
next = curr->next;
for (auto i = 0; i < count; i++) {
curr->next = next->next;
delete next;
next = curr->next;
}
} else {
curr = curr->next;
}
}
auto ans = preHead->next;
delete preHead;
return ans;
}
};