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main.cpp
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104 lines (88 loc) · 2.28 KB
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// Source: https://leetcode.com/problems/remove-nth-node-from-end-of-list
// Title: Remove Nth Node From End of List
// Difficulty: Medium
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Given the `head` of a linked list, remove the `n^th` node from the end of the list and return its head.
//
// **Example 1:**
// https://assets.leetcode.com/uploads/2020/10/03/remove_ex1.jpg
//
// ```
// Input: head = [1,2,3,4,5], n = 2
// Output: [1,2,3,5]
// ```
//
// **Example 2:**
//
// ```
// Input: head = [1], n = 1
// Output: []
// ```
//
// **Example 3:**
//
// ```
// Input: head = [1,2], n = 1
// Output: [1]
// ```
//
// **Constraints:**
//
// - The number of nodes in the list is `sz`.
// - `1 <= sz <= 30`
// - `0 <= Node.val <= 100`
// - `1 <= n <= sz`
//
// **Follow up:** Could you do this in one pass?
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
using namespace std;
struct ListNode {
int val;
ListNode* next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode* next) : val(x), next(next) {}
};
// Count length
class Solution {
public:
ListNode* removeNthFromEnd(ListNode* head, int n) {
auto dummy = new ListNode(0, head); // dummy head
// Count length
auto len = 0;
for (auto node = head; node != nullptr; node = node->next) ++len;
// Find node before target
auto node = dummy;
for (auto i = 0; i < len - n; ++i) node = node->next;
// Delete node
node->next = node->next->next;
head = dummy->next;
delete dummy;
return head;
}
};
// Two pointer
//
// Move first pointer n steps, then move both together
class Solution2 {
public:
ListNode* removeNthFromEnd(ListNode* head, int n) {
auto dummy = new ListNode(0, head); // dummy head
auto fast = dummy;
auto slow = dummy;
// Move fast
for (auto i = 0; i <= n; ++i) fast = fast->next;
// Move both
while (fast != nullptr) {
fast = fast->next;
slow = slow->next;
}
// Delete node
slow->next = slow->next->next;
head = dummy->next;
delete dummy;
return head;
}
};