Glasgow | ITP-SEP-25 | Alaa Tagi | Sprint 2 | Coursework/sprint 2 #886
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Alaa-Tagi
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📅 Sprint 2
cjyuan
reviewed
Nov 25, 2025
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| function countWords(inputString) { | ||
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| const cleanedString = inputString.replace(/[.,!?]/g, '').toLowerCase(); | ||
| const wordsArray = cleanedString.split(/\s+/); | ||
| const wordCount = {}; | ||
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| for (const word of wordsArray) { | ||
| if (wordCount[word] === undefined) { | ||
| wordCount[word] = 1; | ||
| } else { | ||
| wordCount[word]++; | ||
| } | ||
| } | ||
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| return wordCount; | ||
| } |
Contributor
There was a problem hiding this comment.
Change is optional.
Here are some test cases you can try when you have time.
countWords("constructor constructor");
countWords(" Hello World ");
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| test("totalTill calculates the total amount in pounds from the till object", () => { | ||
| const till = { | ||
| "1p": 10, | ||
| "5p": 6, | ||
| "50p": 4, | ||
| "20p": 10, | ||
| }; | ||
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| expect(totalTill(till)).toBe("£4.10"); | ||
| }); | ||
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| // Additional test cases | ||
| test("totalTill returns £0.00 for an empty till", () => { | ||
| const till = {}; | ||
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| expect(totalTill(till)).toBe("£0.00"); | ||
| }); | ||
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| test("totalTill handles tills with only one type of coin", () => { | ||
| const till = { | ||
| "100p": 5, | ||
| }; | ||
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| // d) Write a test for this function to check it works and then fix the implementation of totalTill | ||
| expect(totalTill(till)).toBe("£5.00"); | ||
| }); |
Contributor
There was a problem hiding this comment.
Can your function pass all these tests?
cjyuan
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Alaa-Tagi
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cjyuan
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Nov 27, 2025
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cjyuan
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cjyuan
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Changes are good.
It's best practice to also respond to each of reviewer's comments.
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| recipe.ingredients.forEach(ingredient => { | ||
| console.log(ingredient); | ||
| }); |
Contributor
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This work. Could also explore Array.prototype.join().
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| if (firstEq === -1) { | ||
| // No "=" found → key with empty value | ||
| key = decodeURIComponent(pair); | ||
| value = ""; | ||
| } else { | ||
| key = decodeURIComponent(pair.slice(0, firstEq)); | ||
| value = decodeURIComponent(pair.slice(firstEq + 1)); | ||
| } | ||
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| queryParams[key] = value; |
Contributor
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Could also consider performing the decoding step on line 31.
cjyuan
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