零代码回归测试：解决 Response hint 断言 路径显示 错误

Author: TommyLemon

APIJSON-Java-Server/APIJSONBoot-MultiDataSource/src/main/resources/static/api/apijson/JSONResponse.js

@@ -921,8 +921,8 @@ var JSONResponse = {
     };
 
     var realType = JSONResponse.getType(real);
-    if (type != realType && (type != 'number' || realType != 'integer')) { //类型改变
-      log('compareWithStandard  type != getType(real) >> return COMPARE_TYPE_CHANGE');
+    if (type != realType && type != 'undefined' && (type != 'number' || realType != 'integer')) { //类型改变
+      log('compareWithStandard  type != realType && type != undefined && (type != number || realType != integer) >> return COMPARE_TYPE_CHANGE');
 
       max = {
         code: JSONResponse.COMPARE_TYPE_CHANGE,
@@ -982,7 +982,7 @@ var JSONResponse = {
         }
         log('compareWithStandard  for tk = ' + tk + ' >> ');
 
-        each = JSONResponse.compareWithStandard(firstVal[tk], real[tk], JSONResponse.getAbstractPath(folder,  tk), exceptKeys);
+        each = JSONResponse.compareWithStandard(firstVal[tk], real[tk], JSONResponse.getAbstractPath(folder, tk), exceptKeys);
         if (max.code < each.code) {
           max = each;
         }

APIJSON-Java-Server/APIJSONBoot-MultiDataSource/src/main/resources/static/api/apijson/StringUtil.js

@@ -24,15 +24,15 @@ var StringUtil = {
    * @return
    */
   get: function(s) {
-    return s == null ? '' : s;
+    return s == null ? '' : (JSONResponse.isString(s) ? s : JSON.stringify(s));
   },
 
   /**获取去掉前后空格后的string,为null则返回''
    * @param s
    * @return
    */
   trim: function(s) {
-    return s == null ? '' : s.trim();
+    return StringUtil.get(s).trim();
   },
 
   /**获取去掉所有空格后的string,为null则返回''